Question

In the reaction : $I_2+2S_2{O}_3^{2-}\to 2I^{-}+S_4{O}_6^{2-}$?

• A. $I_2$ is reducing agent
• B. $I_2$ is oxidising agent and $S_2{O}_3^{2-}$ is reducing agent
• C. $S_2{O}_3^{2-}$ is oxidising agent
• D. $I_2$ is reducing agent and $S_2{O}_3^{2-}$ is oxidising agent

Answer 1

The correct option is B $I_2$ is oxidising agent and $S_2{O}_3^{2-}$ is reducing agent

${\stackrel{0}{I}}_2\to 2{\stackrel{0}{I}}^{-}$
$I_2$ undergoes reduction hence acts as oxidising agents.
$S_2^{+2}{O}_6^{2-}\to S_4^{+2.5}{O}_6^{2-}$
It undergoes oxidation hence acts as a reducing agent.