In the reaction $I_{2} + I^{-} \to I_{3}^{-}$ , the Lewis base is

I_{3}^{-}

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I_{2}

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I^{-}

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None of the above

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Solution

The correct option is B $I^{-}$
A Lewis Base is a species that can donate a pair of electrons to an electron acceptor. Here $I^{-}$ is giving electron pair to $I_{2}$ molecule. Therefore $I_{2}$ is a lewis acid and $I^{-}$ is a lewis base.

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Similar questions

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} ⟶ I_{3}^{-}

I_{2}

I_{2} + I^{-} ⟶ I_{3}^{-}

I_{2} + I^{-} ⇌ I_{3}^{-},

I_{3}^{-}

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