Question

In the reaction : $K_4\left[Fe\right(CN{)}_6]+K_{2}C{O}_3\to$ the product formed is :

• A. $FeC{O}_3$
• B. $KCN$
• C. $KFeC{O}_3$
• D. $K_3\left[Fe\right(CN{)}_6]$

Answer 1

The correct option is B $KCN$

$K_{4}Fe(CN{)}_6+K_{2}C{O}_3\to 5KCN+KCNO+Fe+C{O}_2$.

In the above reaction only KCN is formed.

Hence, option B is correct.