Question

In the reaction , $K{I}_{\left(aq\right)}+I_2\to K{I}_3$ (water soluble)

• A. The solution of product possess $4$ ions/mole
• B. In the product, Lewis acid is $K^{+}$
• C. In the product, Lewis acid is $I_3^{-}$
• D. In the solution , Lewis acid is $I_2$

Answer 1

The correct option is D In the solution , Lewis acid is $I_2$

$K{I}_3$ in water will dissociate as,
$K{I}_3\to K^{+}+I_3^{-}$
So, the solution of product possess $2$ ions/mole
Again,
$\underset{\text{Acts as Lewis base}}{KI}+\underset{\text{acts as Lewis acid}}{I_2}⟶K{I}_3$
Since $I_2$ is getting reduced hence it act as lewis acid in solution.