CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the reaction
(CH3)3C−O−CH2CH3+HI(1mole)heat−−−−−−−−−−→
the product(s) formed is(are):

A
(CH3)3COH and CH3CH2I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(CH3)3CI and CH3CH2OH
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(CH3)3CI and CH3CH2I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(CH3)3CO+CH2CH3I|H
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (CH3)3CI and CH3CH2OH
The products formed is are (CH3)3CI (tert butyl iodide) and CH3CH2OH (ethanol).

Thus we get tertiary alkyl iodide and primary alcohol. Above reaction is an example of addition of a molecule of HI to an unsymmetrical ether. The primary alcohol is formed as the tertiary carbocation is more stable. It then reacts with the iodide ion to give the product.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acids and Bases
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon