In the reaction- NH 4 2 Cr 2 O 7 N 2 - H 2 O- Cr 2 O 3The coefficient of H2O is -

The correct option is D 4 (NH_4)_2Cr_2O_7(s) → N_2(g) + #160;4 #160;H_2O(g) + Cr_2O_3(s) To balance the reaction we require 4 moles of H_2O ...

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Heat of Reaction

In the reacti...

Question

In the reaction,
${({N H}_{4})}_{2} {C r}_{2} O_{7} Δ - \to N_{2} + H_{2} O + {C r}_{2} O_{3}$
The coefficient of $H_{2} O$ is :

1

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2

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3

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4

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Similar questions

I : {({N H}_{4})}_{2} {C r}_{2} O_{7} ⟶ N_{2} + {C r}_{2} O_{3} + H_{2} O

I I : {N H}_{4} {N O}_{3} ⟶ N_{2} O + 2 H_{2} O

I I I : 2 K C l O_{3} ⟶ 2 K C l + 3 O_{2}

U O_{2} + {C r}_{2} O_{7}^{2 -} ⟶ U O_{2}^{2 +} + {C r}^{2 +} + H_{2} O

{A l}_{2} O_{3} (s)

{C r}_{2} O_{3} (s)

1596 k J

1134 k J

Δ H

{C r}_{2} O_{3} (s) + 2 A l (s) ⟶ 2 C r (s) + {A l}_{2} O_{3} (s)

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

{C r}_{2} O_{7}^{2 -} + X H^{\oplus} - ----- \to {C r}^{3 +} + H_{2} O

X

X

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