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Question

In the reaction: Me3COCH2CH3+HI(1 mole)Δ

A
Me3COH+CH3CH2I
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B
Me3CI+CH3CH2OH
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C
Me3CI+CH3CH2I
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D
MeCOH+CH3CH2OH
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Solution

The correct option is B Me3CI+CH3CH2OH

Since the tertiary carbocation is more stable, it is formed easily here. The reaction gives alcohol and alkyl iodide since only one mole of HI is used.

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