You visited us 1 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Greater Than Zero

In the reacti...

Question

In the reaction $N_{2} (g) + 3 H_{2} (g) \Leftrightarrow 2 N H_{3} (g)$ the value of the equilibrium constant depends on:

volume of the reaction vessel

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

total pressure of the system

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

the initial concentration of

N_{2}

and

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the temperature

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A volume of the reaction vessel
B total pressure of the system
D the temperature
The value of the equilibrium constant depends on the temperature of the system, total pressure of the system and volume of the reaction vessel.

Suggest Corrections

Similar questions

In the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$ , the value of the equilibrium

constant depends on

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

K_{C} = L^{2} {m o l}^{- 2}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

K_{C} = \frac{{[{N H}_{3}]}^{2}}{[N_{2}] {[H_{2}]}^{3}}

N H_{3}

N_{2}

H_{2}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

[N_{2}] = 1.5 \times 10^{- 2} M

[H_{2}] = 3.0 \times 10^{- 2} M

[N H_{3}] = 1.2 \times 10^{- 2} M

N_{2}, H_{2}

N H_{3}

700

0.036

N_{2}

0.15

H_{2}

K_{c}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

0.29

N H_{3}

Join BYJU'S Learning Program