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Le Chatelier's Principle

In the reacti...

Question

In the reaction $N_{2} O_{4} ⇆ 2 {N O}_{2}$ , the degree of dissociation of $N_{2} O_{4}$ increases with:

increase in temperature

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decrease in temperature

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increase in volume

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presence of catalyst

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Solution

The correct option is C increase in volume
In the reaction $N_{2} O_{4} ⇆ 2 {N O}_{2}$ , the degree of dissociation of $N_{2} O_{4}$ increases with increase in volume. Le Chatlier's principle states that when a system at equilibrium undergoes a change in temperature, volume, or amount of moles present in a reactant or product, the system will respond in order to reach equilibrium. An increase in volume always favors the direction that produces more moles of gas and because in this case there are more moles of products, the reaction will shift to the right and increase the degree of dissociation of $N_{2} O_{4}$ .

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In the reaction N2O4⇆2NO2, the degree of dissociation of N2O4 increases with:

In the reaction $N_{2} O_{4} ⇆ 2 {N O}_{2}$ , the degree of dissociation of $N_{2} O_{4}$ increases with: