Question

In the reaction $N_2{O}_4\leftrightharpoons 2N{O}_2$, the degree of dissociation of $N_2{O}_4$ increases with:

• A. increase in pressure
• B. decrease in temperature
• C. increase in volume
• D. presence of catalyst

Answer 1

The correct option is C increase in volume

For the reaction:

$N_2{O}_4\left(g\right)\leftrightharpoons 2N{O}_2\left(g\right)$

an increase in pressure will shift the equilibrium to less gaseous molecules i.e. left

It is an endothermic reaction, therefore decrease in temperature will shift equilibrium to left

When there is a increase in volume, the equilibrium will shift towards the side of the reaction with more gaseous moles

catalyst changes the rate of reaction and not equilibrium

Therefore an increase in volume will shift the equilibrium to more $N{O}_2$ and will increase the degree of dissociation