In the reaction, $N H_{3 (a q)} + H_{2} O_{(l)} = N H_{4}^{+} (a q) + O H^{-} (a q)$ the ammonium ions is the-

bronsted acid

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bronsted base

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conjugate acid

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conjugate base

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Solution

The correct option is C conjugate acid
The reaction involves formation of ammonium ion from ammonia by accepting a proton from water. Hence, in the given reaction ammonium ion is the conjugate acid of the base ammonia

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Similar questions

{NH}_{3} (aq) + H_{2} O (l) \to {NH}_{4}_{4}^{+} (aq) + {OH}^{-} (aq)

N H_{3} (a q) + H_{2} O (l) ⇌ N H_{4}^{+} (a q) + O H^{-} (a q)

N H_{3} (a q) + H_{2} O (l) ⇌ N H_{4}^{+} + O H^{-} (a q)

N a N H_{2 (s)} + H_{2} O_{(l)} ⇌ N a_{(a q)}^{+} + O H_{(a q)}^{-} + N H_{3 (a q)}

{N H}_{3} (a q) + 2 H_{2} O (l) ⇌ {N H}_{4}^{+} (a q) + {O H}^{-} (a q)

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