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Redox Reactions

In the reacti...

Question

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $C O_{2}$ is:

A

1

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B

10

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C

2

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D

5

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Solution

The correct option is A 1
The balanced reaction of oxalate with permanganate in an acidic medium is

$2 K M n O_{4} + 5 H_{2} C_{2} O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 10 C O_{2} + 8 H_{2} O$

The number of electrons involved in producing one molecule of $C O_{2}$ are :

$= \frac{No.of electron involved in balanced reaction}{No.of moles of C O_{2} produced} = \frac{10}{10} = 1$

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Similar questions

Q. In the reaction of oxalate with permaganate in acidic medium, the number of electrons involved in producing one molecule of

C O_{2}

K M n O_{4}

oxidizes oxalic acid in acidic medium. The number of

C O_{2}

molecules produced as per the balanced equation is:

Q. Permanganate solution reacts with the oxalate ion in acidic medium and forms manganese(II) ion and carbon dioxide. What is the stoichiometric coefficient in front of manganese(II) in the balanced redox equation?

M n O_{4}^{-} + C_{2} O_{4}^{2 -} \to M n^{2 +} + C O_{2}

Q. Which of the following is correct about potassium permanganate for the titration with oxalic acid in acidic medium?

Q. The reaction of the permanganate ion with the oxalate ion in acidic solution forms manganese(II) ion and carbon dioxide. What is the stoichiometric coefficient in front of manganese(II) in the balanced redox equation?

M n O_{4}^{-} + C_{2} O_{4}^{2 -} \to M n^{2 +} + C O_{2}

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