Question

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $C{O}_2$ is:

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> JEE MAIN 2019

Answer 1

The balanced reaction of oxalate with permanganate in an acidic medium is

$2KMn{O}_4+5H_2{C}_2{O}_4+3H_{2}S{O}_4\to K_{2}S{O}_4+2MnS{O}_4+10C{O}_2+8H_{2}O$

The number of electrons involved in producing one molecule of $C{O}_2$ are :

$=\frac{\text{No.of electron involved in balanced reaction}}{\text{No.of moles of}C{O}_2\text{produced}}=\frac{10}{10}=1$