In the reaction of phenol with $C H {C I}_{3}$ and aqueous NaOH at $70^{0}$ C, the electrophile attacking the ring is:

C H {C l}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H {C l}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C {C l}_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C O {C l}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C {C l}_{2}$
In the reaction of phenol with ${C H C l}_{3}$ and aq NaOH at 343K, the electrophile attacking the ring is ${C C l}_{2}$ (Reimer Tiemann Reaction and Carbene formation).

Suggest Corrections

Similar questions

{C H C l}_{3}

N a O H

C H C l_{3}

N a O H

C_{6} H_{5} O H + C H C l_{3} + N a O H \to C_{6} H_{4} (C H O) O H

N a O H

C H {C l}_{3}

340 K

$C_{6} H_{5} O H + C H C l_{3} + N a O H \to$ Salicylaldehyde. The electrophile involved in the above reaction is.

Join BYJU'S Learning Program