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Standard XII

Chemistry

Order of Reaction

In the reacti...

Question

In the reaction, $P + Q ⟶ R + S$ , the time taken for $75$ % reaction of $P$ is twice the time taken for $50$ % reaction of $P$ , when $Q$ is in large quantity. The concentration of $Q$ varies with reaction time as shown in the figure when $P$ is taken in large quantity. The overall order of the reaction is:

2

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Solution

The correct option is D $1$
Concentration of $Q$ is decreasing linearly, hence the order with respect to $Q$ will be zero.
It is only for first order reaction that, $(t_{75} = 2 t_{50})$ hence the order with respect to ' $P$ ' will be one. Overall order $= 1 + 0 = 1$

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Similar questions

Q. In the reaction,

P + Q ⟶ R + S

. The time taken for

75

% reaction of

P

is twice the time taken for

50

% reaction of

P

. The concentration of

Q

varies with reaction time as shown in the figure. The overall order of the reaction is:

Q. In the reaction, P + Q

\to

R + S, the time taken form 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is :

In the reaction,

P + Q \to R + S

, the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is:

In the reaction, P + Q ⟶ R + S

the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is

Q. (a) For a reaction

A + B \to P

,the rate is given by Rate =

k [A] [B]^{2}

(i) How is the rate of reaction affected if the concentration of B is doubled?
(ii) What is the overall order of reaction if A is present in large excess?
(b) A first order reaction takes 23.1 minutes for 50% completion. Calculate the time required for 75% completion of this reaction. (log 2 =0.301, log 3 =0.4771, log 4 =0.6021)

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In the reaction, P+Q⟶R+S, the time taken for 75% reaction of P is twice the time taken for 50% reaction of P, when Q is in large quantity. The concentration of Q varies with reaction time as shown in the figure when P is taken in large quantity. The overall order of the reaction is:

The correct option is D 1Concentration of Q is decreasing linearly, hence the order with respect to Q will be zero.It is only for first order reaction that, (t75=2t50) hence the order with respect to 'P' will be one. Overall order =1+0=1

The correct option is D $1$
Concentration of $Q$ is decreasing linearly, hence the order with respect to $Q$ will be zero.
It is only for first order reaction that, $(t_{75} = 2 t_{50})$ hence the order with respect to ' $P$ ' will be one. Overall order $= 1 + 0 = 1$