In the reaction, P + Q ⟶ R + S

the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C 1
Overall order of reaction can be decided by the data given $t_{75 ﹪} = 2 t_{50 ﹪}$

∴ It is a first order reaction with respect to P.

From graph [Q] is linearly decreasing with time, i.e., order of reaction w.r.t. Q is zero and the rate expression is $r = [P]^{1} [Q]^{0} .$
Therefore 1 is the right answer.

Suggest Corrections

Similar questions

In the reaction, P + Q ⟶ R + S

the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is

Q. In the reaction,

P + Q ⟶ R + S

, the time taken for

75

% reaction of

P

is twice the time taken for

50

% reaction of

P

, when

Q

is in large quantity. The concentration of

Q

varies with reaction time as shown in the figure when

P

is taken in large quantity. The overall order of the reaction is:

In the reaction,

P + Q \to R + S

, the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is:

Q. In the reaction, P + Q

\to

R + S, the time taken form 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is :

Q. In the reaction A + B

\to

C
The time taken for 87.5% reaction of A is thrice the time taken for 50% of the A. The order of reaction w.r.t A is

Join BYJU'S Learning Program