Question

In the reaction: $Ph-CH=CH-C{H}_{2}Br\stackrel{HOH}{\to }\left[X\right]$

$\left[X\right]$ would be:

• A. $Ph-CH=CH-C{H}_{2}OH$
• B. $Ph-\stackrel{OH}{\stackrel{|}{C}}H-CH=C{H}_2$
• C. $Ph-C{H}_2-CH=C{H}_2$
• D. Both (a) and (b)

Answer 1

The correct option is D Both (a) and (b)


There are two pathways through which the reaction can occur.
In (1), substitution takes place at the carbon where the leaving group is attached.
In (2), leaving group departs before the attack of nucleophile. This proceeds via the rearrangement of carbocation.