Question

In the reaction sequence:
$A\underset{}{\overset{Sn{Cl}_2/HCl}{\to }}B\underset{0^o}{\overset{NaN{O}_2/HCl}{\to }}C\underset{}{\overset{H_{2}O/\Delta }{\to }}{C}_6{H}_{5}OH$, $A,B,C$ are:

• A. benzene, nitrobenzene, aniline
• B. nitrobenzene, aniline, and azo-compound
• C. nitrobenzene, benzene, aniline
• D. benzene, amino compound, aniline

Answer 1

The correct option is B nitrobenzene, aniline, and azo-compound

The compounds A, B and C are nitrobenzene, aniline and azo-compound.

The reduction of nitrobenzene with $SnC{l}_2/HCl$ gives aniline.

Diazotization of aniline with $NaN{O}_2/HCl$ at low temperature gives benzene diazonium chloride.

When benzene diazonium chloride is heated in presence of water, phenol is obtained.

$\underset{A}{Ph-N{O}_2}\underset{}{\overset{Sn{Cl}_2/HCl}{\to }}\underset{B}{Ph-N{H}_2}\underset{0^o}{\overset{NaN{O}_2/HCl}{\to }}\underset{C}{Ph{N}_{2}Cl}\underset{}{\overset{H_{2}O/\Delta }{\to }}{C}_6{H}_{5}OH$