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Byju's Answer
Standard XII
Chemistry
Preparation of Carboxylic Acids
In the reacti...
Question
In the reaction sequence,
[
X
]
is:
[
X
]
K
M
n
O
4
/
⊖
O
H
→
H
O
O
C
−
(
C
H
2
)
3
−
C
H
3
|
C
−
H
−
C
O
O
H
.
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Solution
K
M
n
O
4
in alkaline solution is a weak oxidizing agent. It can oxidize aldehyde to carboxylic acidonly.
Therefore,
O
H
C
−
(
C
H
2
)
3
−
C
H
3
|
C
|
H
−
C
H
O
K
M
n
O
4
/
O
H
−
−
−−−−−−−−
→
H
O
O
C
−
(
C
H
2
)
3
−
C
H
3
|
C
|
H
−
C
O
O
H
[
X
]
Therefore,
[
X
]
is
O
H
C
−
(
C
H
2
)
3
−
C
H
3
|
C
|
H
−
C
H
O
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Similar questions
Q.
G
l
u
c
o
s
e
A
g
2
O
→
X
G
l
u
c
o
s
e
C
o
n
c
.
H
N
O
3
→
Y
X. Y and X respectively are:
Q.
C
H
3
−
O
H
|
C
H
−
C
H
2
−
C
H
2
−
O
|
|
C
−
C
H
3
→
C
H
3
−
O
H
|
C
H
−
(
C
H
2
)
3
−
C
H
3
.
Given conversion can be achieved by:
Q.
In the reaction sequence,
C
6
H
5
C
H
O
N
H
2
O
H
/
H
+
−
−−−−−−−
→
△
(
X
)
P
2
O
5
−
−−
→
△
(
Y
)
H
2
O
/
H
+
−
−−−−
→
(
Z
)
X
,
Y
and
Z
respectively are:
Q.
C
H
3
−
C
H
2
−
C
O
O
H
+
B
r
2
P
B
r
3
−
−−
→
C
H
3
−
C
|
B
r
H
−
C
O
O
H
H
2
O
,
C
H
3
N
H
2
−
−−−−−−−−
→
C
H
3
−
C
|
N
H
2
H
−
C
O
O
H
The following sequence of reaction affords :
Q.
Compound (A) on oxidation with hot
K
M
n
O
4
/
O
H
−
gives two compounds (in the figure) Compound A will have a structure:
C
H
3
−
C
H
|
−
C
H
3
C
O
O
H
&
C
H
3
−
O
|
|
C
−
C
H
2
C
H
2
C
H
3
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