Question

In the reaction sequence, X, Y, Z will be:
Here X is monochlorinated product.
$\text{Cyclohexane}\stackrel{{\text{hv/Cl}}_2}{\to }\left(X\right)\stackrel{\text{alc. KOH/}\Delta }{\to }\left(Y\right)\underset{\left(ii\right)H_{2}O/Zn}{\overset{\left(i\right)O_3}{\to }}\left(Z\right)$ will be:

• A. Hexanal
• B. 2-Hexanone
• C. 3-Hexanone
• D. Hexanedial

Answer 1

The correct option is D Hexanedial

Monochlorination of cyclohexane with chlorine in presence of light gives chlorocyclohexane.

Dehydrohalogenation in presence of alkaline $KOH$, gives cyclohexene.

Ozonolysis by reduction gives hexanedial.