Question

In the reaction $SnC{l}_2+C{l}_2\to SnC{l}_4+2e^{-}$, the lewis acid is:

• A. $SnC{l}_4$
• B. $SnC{l}_3$
• C. $SnC{l}_2$
• D. $SnCl$

Answer 1

The correct option is C $SnC{l}_2$

In the reaction $SnC{l}_2+C{l}_2\to SnC{l}_4+2e^{-}$, the Lewis acid is $SnC{l}_2$.
Note: A Lewis acid is electron pair acceptor.
Chlorine atoms donate electron pairs to Sn atom in $SnC{l}_2$ to form coordinate covalent bonds in $SnC{l}_4$.