Question

In the reaction $VO+F{e}_2{O}_3\to FeO+V_2{O}_5$, what is the n-factor for $V_2{O}_5$?

Answer 1

$VO+F{e}_2{O}_3⟶FeO+V_2{O}_5$

In $VO,$ oxidation state of $V=+2$

In $V_2{O}_5,$ oxidation state of $V=+5$

$n$ $factor$ $of$ $V_2{O}_5=no.$ $of$ $V$ $in$ $V_2{O}_5\times Magnitude$ $of$ $change$ $in$ $oxidation$ $state$.

$=2\times (5-2)=2\times 3=6$