In the redox reaction-10 FeC2O4 - xKMnO4 - 24H2SO4 - 5Fe2SO43 - 20CO2 - y MnSO4 - 3K2SO4-24H2Othe value of x and y are- respectively-

The balanced redox reaction given above can be written as: 10 FeC_2O_4 + 6KMnO_4 + 24H_2SO_4 → nbsp; 5Fe_2(SO_4)_3 + 20CO_2 + 6MnSO_4 + 3K_2SO_4 + 24H_2O So t ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Equivalent Mass

In the redox ...

Question

In the redox reaction,
$10 F e C_{2} O_{4} + x K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + y M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
the value of $x$ and $y$ are, respectively:

6, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6, 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6, 6$
The balanced redox reaction given above can be written as:
$10 F e C_{2} O_{4} + 6 K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + 6 M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
So the value of $x = 6$ and $y = 6$

Suggest Corrections

Similar questions

Q. Given :

X N a_{2} H A s O_{3} + Y N a B r O_{3} + Z H C l \to N a B r + H_{3} A s O_{4} + N a C l

The values of X, Y and Z in the above redox reaction are respectively:

Q. For the redox reaction,

x M n O_{4}^{-} + y C_{2} O_{4}^{2 -} + z H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

, the value of

x, y

and

z

for the balanced reaction are, respectively :

$x K M n O_{4} + y K_{2} C_{2} O_{4} + z H_{2} S O_{4} ⟶ a M n O_{4} + b C O_{2} + 6 K_{2} S O_{4} + 8 H_{2} O$

Here x,y,z, a and b are respectively

Q. Consider a redox reaction :

x N a_{2} H A s O_{3} + y N a B r O_{3} + z H C l \to N a B r + H_{3} A s O_{4} + N a C l

where

x, y, z

are the stoichiometric coefficients of

N a_{2} H A s O_{3}, N a B r O_{3}, H C l

respectively.
The value of

x + y + z

in the above balanced redox reaction is :

Q. Consider the following redox reaction:

M n (O H)_{2} (s) + M n O_{4}^{-} (a q) \to M n O_{2} (s)

x, y, z

are the stoichiometric coefficients of

M n (O H)_{2}, M n O_{4}^{-}

and

M n O_{2}

respectively when the above reaction is balanced in basic medium.
What will be the value of

x + y + z

Join BYJU'S Learning Program

In the redox reaction, 10FeC2O4+xKMnO4+24H2SO4→5Fe2(SO4)3+20CO2+yMnSO4+3K2SO4+24H2O the value of x and y are, respectively:

The correct option is D 6, 6The balanced redox reaction given above can be written as: 10FeC2O4+6KMnO4+24H2SO4→5Fe2(SO4)3+20CO2+6MnSO4+3K2SO4+24H2O So the value of x=6 and y=6

In the redox reaction,
$10 F e C_{2} O_{4} + x K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + y M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
the value of $x$ and $y$ are, respectively:

The correct option is D $6, 6$
The balanced redox reaction given above can be written as:
$10 F e C_{2} O_{4} + 6 K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + 6 M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
So the value of $x = 6$ and $y = 6$