In the redox reaction-10 FeC2O4 - xKMnO4 - 24H2SO4 - 5Fe2SO43 - 20CO2 - y MnSO4 - 3K2SO4-24H2Othe value of x and y are- respectively-

The balanced redox reaction given above can be written as: 10 FeC_2O_4 + 6KMnO_4 + 24H_2SO_4 → nbsp; 5Fe_2(SO_4)_3 + 20CO_2 + 6MnSO_4 + 3K_2SO_4 + 24H_2O So t ...

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Byju's Answer

Standard XII

Chemistry

Equivalent Mass

In the redox ...

Question

In the redox reaction,
$10 F e C_{2} O_{4} + x K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + y M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
the value of $x$ and $y$ are, respectively:

6, 3

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3, 6

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3, 3

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6, 6

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Solution

The correct option is D $6, 6$
The balanced redox reaction given above can be written as:
$10 F e C_{2} O_{4} + 6 K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + 6 M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
So the value of $x = 6$ and $y = 6$

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In the redox reaction, 10FeC2O4+xKMnO4+24H2SO4→5Fe2(SO4)3+20CO2+yMnSO4+3K2SO4+24H2O the value of x and y are, respectively:

The correct option is D 6, 6The balanced redox reaction given above can be written as: 10FeC2O4+6KMnO4+24H2SO4→5Fe2(SO4)3+20CO2+6MnSO4+3K2SO4+24H2O So the value of x=6 and y=6

In the redox reaction,
$10 F e C_{2} O_{4} + x K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + y M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
the value of $x$ and $y$ are, respectively:

The correct option is D $6, 6$
The balanced redox reaction given above can be written as:
$10 F e C_{2} O_{4} + 6 K M n O_{4} + 24 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + 20 C O_{2} + 6 M n S O_{4} + 3 K_{2} S O_{4} + 24 H_{2} O$
So the value of $x = 6$ and $y = 6$