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Second Law of Motion

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Question

In the relation Kinetic Energy = p²/2m (where p is momentum, m is mass ) . If Momentum is raised by 0.1 % what will be the percentage increase in Kinetic Energy

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Solution

Kinetic energy E=P22m∴E∝P2

Percentage increase in kinetic energy = 2(% increase in momentum) [If change is very small]
= 2(0.1%) = 0.2%.

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