In the relation P - e - x- nR- P is power- x is distance- n is number of moles- R is gas constant and - is temperature- The dimensional formula of - isA- - M 0 L 0 T 0-B- - M 1 L 0 T 1-C- - M 0 L -1 T 1-D- - M 0 L -1 T -1-

The correct option is C [M^0L^ 1T^1] α=nRθ/x=joule/meter β=α/p=joule/meter×sec/joule=[M^0L^ 1T] ...

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Byju's Answer

Standard XII

Physics

Conduction Law

In the relati...

Question

In the relation $P = \frac{α}{β} e^{\frac{α x}{n R θ}}$ , P is power, x is distance, n is number of moles, R is gas constant and $θ$ is temperature. The dimensional formula of $β$ is

$[M^{0} L^{0} T^{0}]$

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$[M^{1} L^{0} T^{1}]$

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$[M^{0} L^{- 1} T^{1}]$

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$[M^{0} L^{- 1} T^{- 1}]$

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Solution

The correct option is C
$[M^{0} L^{- 1} T^{1}]$

$α = \frac{n R θ}{x} = \frac{j o u l e}{m e t e r}$

$β = \frac{α}{p} = \frac{j o u l e}{m e t e r} \times \frac{s e c}{j o u l e} = [M^{0} L^{- 1} T]$

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In the relation P=αβ eαxnRθ, P is power, x is distance, n is number of moles, R is gas constant and θ is temperature. The dimensional formula of β is

The correct option is C [M0L−1T1] α=nRθx=joulemeter β=αp=joulemeter×secjoule=[M0L−1T]

In the relation $P = \frac{α}{β} e^{\frac{α x}{n R θ}}$ , P is power, x is distance, n is number of moles, R is gas constant and $θ$ is temperature. The dimensional formula of $β$ is

The correct option is C
$[M^{0} L^{- 1} T^{1}]$

$α = \frac{n R θ}{x} = \frac{j o u l e}{m e t e r}$

$β = \frac{α}{p} = \frac{j o u l e}{m e t e r} \times \frac{s e c}{j o u l e} = [M^{0} L^{- 1} T]$