Question

In the relation : $\frac{dy}{dt}=2\omega sin(\omega t+\varphi )$, the dimensional formula for $(\omega t+\varphi )$ is

• A. [MLT]
• B. $\left[ML{T}^0\right]$
• C. $\left[M^1{L}^0{T}^0\right]$
• D. $\left[M^0{L}^0{T}^0\right]$

Answer 1

The correct option is D

$\left[M^0{L}^0{T}^0\right]$

$Here(\omega t+\varphi )$ is dimensionless because it is an argument of a trigonometric function.