Question

In the respect of the equation, $k=A{e}^{-E_a/RT}$ in chemical kinetics, which one of the following statement is correct?

• A. $k$ $\text{is equilibrium constant}$
• B. $A$ $\text{is adsorption}$
• C. $E_a$ $\text{is activation energy}$
• D. $R$ $\text{is Rydberg constant}$

Answer 1

The correct option is C $E_a$ $\text{is activation energy}$

$k=A{e}^{-E_a/RT}$ ------------ 1

where,

$k=$ rate constant
$A=$ pre-exponential frequency factor
$E_a=$ activation energy
$R=$ gas constant
$T=$ temperature in Kelvin scale