Question

In the reversible reaction $2HI\rightleftharpoons H_2+I_2,K_p$ is:

• A. equal to $K_c$
• B. greater than $K_c$
• C. $0$
• D. less than $K_c$

Answer 1

Answer: (A)

equal to $K_c$

Solution:- equal to $K_c$

As we know that,

$K_p=K_c{\left(RT\right)}^{\Delta n_g}$

$2{HI}_{\left(g\right)}\rightleftharpoons {H_2}_{\left(g\right)}+{I_2}_{\left(g\right)}$

For the above reaction,

$\Delta n_g=n_P-n_R=(1+1)-2=0$

Therefore,

$K_p=K_c{\left(RT\right)}^0$

$\Rightarrow K_p=K_c$

Hence for the given reaction, $K_p$ is equal to $K_c$.