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Question

In the right-angled ΔABC, cotA.cotB.cotC=...........

A
1
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B
0
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C
2
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D
None of these
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Solution

The correct option is B 0
ABC be a right angled triangle.
cotA.cotB.cotC= ABBC×0×BCAB=0
Hence option B is correct.
234134_202594_ans_4648f9de38474babb4f569f7bf6fd8f4.png

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