In the right-angled triangle $Q P R$ , $P M$ is an altitude.
Given that $Q R = 8 c m$ and $M Q = 3.5 c m$ , calculate the value of $P R$ ?

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Solution

$∠ Q P R = ∠ P M R = 90 °$

$∠ P R Q = ∠ P R M (c o m m o n)$

$Δ P Q R = Δ M P R$ ( $A A$ similarity)

$\frac{Q R}{P R} = \frac{P R}{M R}$

${P R}^{2} = 8 * 4.5 = 36$

$P R = 6 c m$

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In the right-angled triangle QPR, PM is an altitude. Given that QR=8 cm and MQ=3.5 cm, calculate the value of PR ?

∠QPR=∠PMR=90°∠PRQ=∠PRM(common)ΔPQR=ΔMPR(AA similarity)QRPR=PRMRPR2=8∗4.5=36PR=6cm

In the right-angled triangle $Q P R$ , $P M$ is an altitude.
Given that $Q R = 8 c m$ and $M Q = 3.5 c m$ , calculate the value of $P R$ ?

$∠ Q P R = ∠ P M R = 90 °$

$∠ P R Q = ∠ P R M (c o m m o n)$

$Δ P Q R = Δ M P R$ ( $A A$ similarity)

$\frac{Q R}{P R} = \frac{P R}{M R}$

${P R}^{2} = 8 * 4.5 = 36$

$P R = 6 c m$