Question

In the right triangle in Figure, if $\theta ={42}^o$, find the value of $x$.

• A. $4.9$
• B. $5.8$
• C. $6.7$
• D. $8.1$
• E. $9.0$

Answer 1

The correct option is C $6.7$

By sine rule, we get
$\frac{6}{\sin \theta }=\frac{x}{\sin (90-\theta )}$
$\Rightarrow 6\times \frac{\cos \theta }{\sin \theta }=6\cot \theta =6\cot 42=6.7$