Question

In the Rosenmund's reaction,

$RCOCl+H_2\stackrel{Pd/BaS{O}_4}{\to }RCHO+HCl$

Here $BaS{O}_4$:

• A. promotes catalytic activity of $Pd$
• B. removes the $HCl$ formed in the reaction
• C. deactivates palladium
• D. activates palladium

Answer 1

The correct option is C deactivates palladium

In the Rosenmund's reaction, acid chlorides are converted to corresponding aldehydes by catalytic reduction.

The reaction is carried out by passing through a hot solution of the acid chloride in the presence of Pd deposited over $BaS{O}_4$.

Here, barium sulphatedecrease the activity of palladium.

$RCOCl+H_2\stackrel{Pd/BaS{O}_4}{\to }RCHO+HCl$

Option C is correct.