In the same figure, if $y > x > z;$ arrange sides $A B, B C$ and $A C$ in descending order according their lengths.

B C > A B > A C

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A B > B C > A C

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B C > A B < A C

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None of these

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Solution

The correct option is B $A B > B C > A C$
$Since, y > x > z; ∠ A = 180 - x ∠ B = 180 - y (y i s t h e l a r g e s t, s o ∠ B i s t h e s m a l l e s t) ∠ C = 180 - z (z i s t h e s m a l l e s t, S o ∠ C i s t h e l a r g e s t) s o ∠ C > ∠ A > ∠ B S o A B > B C > A C (A n g l e s i d e r e l a t i o n s h i p)$

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In the given figure if $∠$ BAC = $60^{\circ}$ , AB = AC = 6cm then find the length of BC.

If $A B > A C > B C,$ arrange the angles $x, y$ and $z$ in decending order of their values.

In the given figure
if $∠ B A C = 60^{\circ}$ , AB = AC, then

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