Question

In the school ground, there is a pit in the shape of a regular hexagon, to collect rain-water. Each side of the pit is 2 metres long and the pit is 3 metres deep. It contains water 1 metre high. How many litres is it?

Answer 1

Height of the pit = 3 m

Height of water in the pit = 1 m

Length of side of the regular hexagon = 2 m

Diagonals of a regular hexagon divide it into six equilateral triangles.

∴ Area of the regular hexagon =

Volume of water = Area of the regular hexagon × Height of water

We know that 1 m³ = 1000 L

∴ 10.38 m³ = 1000 × 10.38 L = 10380 L

Thus, the pit contains 10380 litres of rain-water.