In the semicircle shown, the top chord is parallel to the diameter. What is its length?
10 cm
Given RS = 1 cm
AB = 26 cm (diameter)
∴ AO = OP = 13 cm (radius)
OR = OS - SR = 13 - 1 = 12 cm
We know, in a circle, the square of half the length of a chord is the difference of the squares of the radius and the perpendicular distance of the chord from the centre of the circle.
⟹ PR = √OP2−OR2 = √132−122 = √169−144 = 5 cm
∴ PQ = 2 × PR = 2 × 5 = 10 cm