wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the series circuit shown in figure, for series resonance, the value of the coupling coefficient k will be

A
0.25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.999
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.25
At resonance

XLXC=0

|XL|=|XC|

|XL|=|j12|

XL=j12

XL=XL1+XL2+2kXL1×XL2

XL=j2+j8+2kj2×j8=j12

2kj4=j2

k=0.25


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dimensional Analysis
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon