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P-N Junction

In the series...

Question

In the series L-C-R circuit figure, the voltmeter and ammeter readings are

A

V

=

100 v o l t, I

=

2 a m p

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B

V

=

100 v o l t, I

=

5 a m p

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C

V

=

1000 v o l t, I

=

2 a m p

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D

V

=

300 v o l t, I

=

1 a m p

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Solution

The correct option is A $V$ = $100 v o l t, I$ = $2 a m p$
Here, $V_{L} = V_{C}$ .

$V_{L}$ and $V_{C}$ are in oppositr phases. Hence they will cancel each other. Now the resultant potential difference is equal to the applied potential difference.

i.e. $V = 100 V$

Impedence, $Z = R (X_{L} o r X_{C})$

Therefore,

$I_{r m s} = \frac{V_{r m s}}{Z} = \frac{V_{r m s}}{R} = \frac{100}{50} = 2 A$

So, the voltmeter reading is $100 V$ and ammeter reading is $2 A$ .

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