Question

In the series $Sc$ $(Z=21)$ to $Zn$ $(Z=30)$, the enthalpy of atomization of zinc is the lowest. i.e. $126kJmo{l}^{-1}$. Why?

Answer 1

$\Rightarrow$ The extent of metallic bonding, an element is under going decides the enthalphy of adomisation.

$\Rightarrow$ In all transition metals (except $Zn$ $\left({3d}^{10}{4S}^2\right)$), there are same unpaired $e^{-}s$ that accounts for strong metallic bonding due to the absence of unpaired $e^{-}$ in zinc, the inter-atomic electronic bonding is weakest in $Zn$, as result has least enthalphy of atomisation.