In the shown circuit- all three capacitor are indentical and have capacitance C - F each- Each resistor has resistance of R - An ideal cell of emf V volts is connected as shown- Then the magnitude of potential difference across capacitor C3 in steady state is -

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Parallel Combination of Cells

In the shown ...

Question

In the shown circuit, all three capacitor are indentical and have capacitance $C μ F$ each. Each resistor has resistance of $R Ω$ . An ideal cell of emf $V$ volts is connected as shown. Then the magnitude of potential difference across capacitor $C_{3}$ in steady state is :

\frac{V}{3}

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\frac{V}{2}

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\frac{2}{9} V

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\frac{3}{4} V

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Solution

The correct option is C $\frac{2}{9} V$
The charge in the encircled region is zero.
$Q = C V$
$∴ C (V^{'} - 2 V / 3) + C (V^{'} - 2 V / 3) + C (V^{'} - V / 3) = 0$
$\Rightarrow 3 V^{'} = 5 V / 3 \Rightarrow V^{'} = 5 V / 9$
Potential across the required capacitor $= 5 V / 9 - V / 3 = 2 V / 9$

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In the shown circuit, all three capacitor are indentical and have capacitance CμF each. Each resistor has resistance of RΩ. An ideal cell of emf V volts is connected as shown. Then the magnitude of potential difference across capacitor C3 in steady state is :

The correct option is C 29VThe charge in the encircled region is zero.Q=CV∴C(V′−2V/3)+C(V′−2V/3)+C(V′−V/3)=0⇒3V′=5V/3⇒V′=5V/9Potential across the required capacitor =5V/9−V/3=2V/9

In the shown circuit, all three capacitor are indentical and have capacitance $C μ F$ each. Each resistor has resistance of $R Ω$ . An ideal cell of emf $V$ volts is connected as shown. Then the magnitude of potential difference across capacitor $C_{3}$ in steady state is :

The correct option is C $\frac{2}{9} V$
The charge in the encircled region is zero.
$Q = C V$
$∴ C (V^{'} - 2 V / 3) + C (V^{'} - 2 V / 3) + C (V^{'} - V / 3) = 0$
$\Rightarrow 3 V^{'} = 5 V / 3 \Rightarrow V^{'} = 5 V / 9$
Potential across the required capacitor $= 5 V / 9 - V / 3 = 2 V / 9$