In the shown circuit, the heat produced in the 5Ω resistor due to the current flowing through it is 10 calories per second. The heat generated in the 4Ω resistors is?
A
1 cal/sec
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B
2 cal/sec
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C
3 cal/sec
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D
4 cal/sec
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Solution
The correct option is D2 cal/sec H=I2Rt→(1)
Given:
H=10caloriesR=5Ω
Current can be evaluated from equation (1)
10=I2×5×t105=I2t=2=(I2)2×t=(24)→(2)
Heat generated in 4Ω resistance is
Let H1
And we know that current is ∝1R
Here in this branch (4Ω resistance is 10Ω so current will be half of 5Ω (branch)