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Standard XII

Physics

Limiting Friction

In the shown ...

Question

In the shown fig. Block A and B are of mass $1$ kg each and surfaces are ll smooth. Spring constant is $k = 60 N / c m$ . The system is in equilibrium. The minimum mass of block C for which when block C is suddenly removed the block A leaves contact from support is :-

1.2 k g

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0.6 k g

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0 k g

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2 k g

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Solution

The correct option is C $0 k g$
Force on Block A,
$= 10 \times 1 \times \frac{3}{5} = 6 N$
$\Rightarrow x = \frac{6}{60} = .1 m$
So, expansion required is
$x = 0.1 m$
Now,
$(B + C) g sin θ = k x$
$(10 + C) \frac{3}{5} = 60 \times 0.1$
$C = 0 k g$
So, Only energy will be considered.

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In the shown fig. Block A and B are of mass 1kg each and surfaces are ll smooth. Spring constant is k=60N/cm. The system is in equilibrium. The minimum mass of block C for which when block C is suddenly removed the block A leaves contact from support is :-

The correct option is C 0kgForce on Block A,=10×1×35=6N⇒x=660=.1mSo, expansion required is x=0.1mNow,(B+C)gsinθ=kx(10+C)35=60×0.1C=0kgSo, Only energy will be considered.

In the shown fig. Block A and B are of mass $1$ kg each and surfaces are ll smooth. Spring constant is $k = 60 N / c m$ . The system is in equilibrium. The minimum mass of block C for which when block C is suddenly removed the block A leaves contact from support is :-

The correct option is C $0 k g$
Force on Block A,
$= 10 \times 1 \times \frac{3}{5} = 6 N$
$\Rightarrow x = \frac{6}{60} = .1 m$
So, expansion required is
$x = 0.1 m$
Now,
$(B + C) g sin θ = k x$
$(10 + C) \frac{3}{5} = 60 \times 0.1$
$C = 0 k g$
So, Only energy will be considered.