In the shown figure, find the potential drop across 4μF capacitor and 6Ω resistor (at steady state)
A
0,0
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B
0,3V
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C
0,2V
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D
2V,0
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Solution
The correct option is D2V,0 I=32+4=12A
Potential drop across 4Ω resistor is V=4×12=2V
The whole potential drop occurs across 4μFcapacitor as current does not exist in the branch containing capacitor. Hence the drop across 6Ω resistor is zero.