In the shown figure. If F=20N,m1=m2=3kg and the acceleration is 0.5m/s2. What will be the tension in the connecting cord if the friction forces on the two blocks are equal? How large is the frictionless force on either block.
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Solution
Let us first consider the 2 masses as a single object. Total mass =3+3=6kg
Resultant force, F=ma
F→6×0.5=3N
Since an external force of 20N is being applied, the frictional force must be 20−3=17N
(8.5N on each mass).
Now consider m1 by itself. The resultant force on it F=ma=3×0.5=1.5N
Let T=tensioninropejoiningm1andm2
The only 2 horizontal forces on m1 are T (to right) and 8.5N (friction to the left)