In the shown figure, line segment $B D$ is angle bisector of $∠ A B C$ . Line segment $B E$ is angle bisector of $∠ A B D$ . Then $∠ A B C =$ __ $\times ∠ A B E$

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Solution

As stated in question line segment $B D$ is angle bisector so, $A B D = D B C$ .

So, $∠ A B C = 4 ∠ A B E$

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In the shown figure, line segment BD is angle bisector of ∠ABC. Line segment BE is angle bisector of ∠ABD. Then ∠ABC= __ ×∠ABE

As stated in question line segment BD is angle bisector so, ABD=DBC. So, ∠ABC=4∠ABE

In the shown figure, line segment $B D$ is angle bisector of $∠ A B C$ . Line segment $B E$ is angle bisector of $∠ A B D$ . Then $∠ A B C =$ __ $\times ∠ A B E$

As stated in question line segment $B D$ is angle bisector so, $A B D = D B C$ .

So, $∠ A B C = 4 ∠ A B E$