In the shown figure, the bill A is released from rest, when the spring is at its natural (unstretched) length. For the block B of mass M to leave contact with ground at some stage, the minimum mass of A must be

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M/2

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M/4

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Solution

The correct option is D M/2
Let the mass of the bill be $m$ and it is given that mass of Block be is $M$

$k x = M g$

$\Rightarrow x = \frac{M g}{k}$

$\Rightarrow \frac{1}{2} k x^{2} = m g x$

$\Rightarrow \frac{1}{2} k \frac{M g}{k} = m g$

$\Rightarrow m = \frac{M}{2} .$

Hence, the answer is $\frac{M}{2} .$

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In the shown figure, the bill A is released from rest, when the spring is at its natural (unstretched) length. For the block B of mass M to leave contact with ground at some stage, the minimum mass of A must be

The correct option is D M/2Let the mass of the bill be m and it is given that mass of Block be is Mkx=Mg⇒x=Mgk⇒12kx2=mgx⇒12kMgk=mg⇒m=M2.Hence, the answer is M2.