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Question

In the shown figure, the strings are massless. If the vertical rod is rotated the tension in upper string is 35 N then the speed of the ball is


A
5.4 m/s
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B
4.4 m/s
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C
3.4 m/s
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D
6.4 m/s
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Solution

The correct option is D 6.4 m/s
FBD of the ball,

From vertical equilibrium ,

mg+T2sin30=T1sin30

1.34×10+T2×12=35×12

T2=8.2 N

From horizontal equilibrium,

T1cos30+T2cos30=mv2r

35×cos30+8.2×cos30=1.34×v21.70cos30

35×34+8.2×34=1.34×v21.70

32.4×1.701.34=v2

v=32.4×1.701.34=6.4 m/s

Hence, option (d) is the correct answer.

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