Question

In the shown network, charge on $2\mu F$ capacitor in steady state would be :

• A. $10\mu C$
• B. $20\mu C$
• C. $5\mu C$
• D. $40\mu C$

Answer 1

The correct option is A $10\mu C$

As we have to find charge are capacitor of $2\mu f$, but the capacitor is in steady-state this current through this is zero.

The potential at one point of a capacitor is $10V$ whereas other terminal is connected to negative terminal of battery.

thus it is $OV$

$\therefore$ charge on capacitor is

$q=CV$

$q=2\times \left(10\right)$

$=20$