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Charge Behaviour

In the shown ...

Question

In the shown system $m_{1} > m_{2}$ . Thread $Q R$ is holding the system. If this thread is cut, then just after cutting :

acceleration of mass

m_{1}

is zero and that of

m_{2}

is directed upward

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acceleration of mass

m_{2}

is zero and that of

m_{2}

is directed upward

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acceleration of both the blocks will be same

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acceleration of system is given by

(\frac{m_{1} - m_{2}}{m_{1} + m_{2}}) k g

, where

k

is a spring factor

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Solution

The correct option is A acceleration of mass $m_{1}$ is zero and that of $m_{2}$ is directed upward
On cutting the string the resultant force of $m_{1}$ remains zero because its weight is balanced by the tension in the spring. but on block $m_{2}$ a resultant upward force $(m_{1} - m_{2}) g$ is developed. This block $m_{1}$ will have no resultant acceleration whereas $m_{2}$ does have an upward acceleration of $\frac{(m_{1} - m_{2}) g}{m_{2}}$ .

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