In the shown the cells A and B have negligible resistance- For VA-12 V- R1-500 - and R-100 - the galvanometer G shows no deflection- The value of VB is-

The correct option is D 2 V Applying Kirchoff's law 500I+100I=12 So, I=12×10^ 26=2×10^ 2 Hence, V_B=IR=100(2×10^ 2)=2 V ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Non-Ideal Battery

In the shown ...

Question

In the shown the cells $A$ and $B$ have negligible resistance. For $V_{A} = 12 V, R_{1} = 500 Ω$ and $R = 100 Ω$ the galvanometer $(G)$ shows no deflection. The value of $V_{B}$ is:

12 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2 V$
Applying Kirchoff's law
$500 I + 100 I = 12$
So, $I = \frac{12 \times 10^{- 2}}{6} = 2 \times 10^{- 2}$
Hence, $V_{B} = I R = 100 (2 \times 10^{- 2}) = 2 V$

Suggest Corrections

Similar questions

Q. In the circuit shown below, the cells A and B have negligible resistance. For

V_{A} = 12 V, R_{1} = 500 Ω

and

R = 100 Ω

, the galvanometer (G) shows no deflection. The value of

V_{B}

is:

Q. In the circuit shown the cells A and B have negligible resistances. For

V_{A} = 12

R_{1} = 500 Ω

and

R = 100 Ω

the galvanometer (G) shows no deflection. The value of

V_{B}

is :-

Q. A battery of emf

E_{0}

= 12V is connected across a 4m long uniform wire having resistance

\frac{4 Ω}{m}

. The cells of small emfs

ε_{1}

= 2V and

ε_{2}

= 4V having internal resistance

2 Ω

and

6 Ω

respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N, find the distance of point N from the point A.

In the circuit shown, the galvanometer shows zero deflections. The batteries have negligible internal resistance. The value of the resistor R is

Q. A battery of emf

E_{0} = 12 V

is connected across a

4 m

long uniform wire having resistance

4 Ω / m

. The cells of small emfs

ϵ_{1} = 2 V

and

ϵ_{2} = 4 V

having internal resistance

2 Ω

and

6 Ω

respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point

N

, the distance of point

N

from the point

A

is equal to

Join BYJU'S Learning Program

In the shown the cells A and B have negligible resistance. For VA=12 V,R1=500 Ω and R=100 Ω the galvanometer (G) shows no deflection. The value of VB is:

The correct option is D 2 VApplying Kirchoff's law500I+100I=12So, I=12×10−26=2×10−2Hence, VB=IR=100(2×10−2)=2 V

In the shown the cells $A$ and $B$ have negligible resistance. For $V_{A} = 12 V, R_{1} = 500 Ω$ and $R = 100 Ω$ the galvanometer $(G)$ shows no deflection. The value of $V_{B}$ is:

The correct option is D $2 V$
Applying Kirchoff's law
$500 I + 100 I = 12$
So, $I = \frac{12 \times 10^{- 2}}{6} = 2 \times 10^{- 2}$
Hence, $V_{B} = I R = 100 (2 \times 10^{- 2}) = 2 V$