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Silver Nitrate Test

In the silver...

Question

In the silver nitrate test, we confirm the compound given to be $H C l$ due to the formation of a white precipitate. This white precipitate is .

A

A g C l

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B

H N O_{3}

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C

A g N O_{3}

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Solution

The correct option is A $A g C l$
In the silver nitrate test, the given compound is made to react with $A g N O_{3}$ . The compound is confirmed to be $H C l$ if a white coloured precipitate is formed. This is due to the formation of $A g C l$ .

$A g N O_{3} (a q) + H C l (a q) \to A g C l (↓) + H N O_{3} (a q)$
$(w h i t e)$

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